Sampling Distribution of the Sample Proportion Calculator

Find the mean and standard error of a sample proportion.

Mean 0.4
Standard error 0.049

Formula: mean = p; SE = √(p(1−p)/n)

Step-by-step with your numbers:
1. Values used:
2. Population proportion = 0.4
3. Sample size = 100
4.
5. Mean = (0.4 / 100) x 100 = 0.004 x 100 = 0.4
6. Standard error = 0.049
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The distribution of sample proportions is centered on p with a predictable spread.

How the Math Works

The Sampling Distribution of the Sample Proportion Calculator uses two fundamental formulas to analyze how sample proportions behave. The mean of the sampling distribution equals the population proportion (p), which means on average, sample proportions will match the true population proportion. The standard error is calculated as the square root of p times (1 minus p) divided by n, where n is the sample size. This formula shows that variability in sample proportions decreases as sample size increases, following the principle that larger samples provide more reliable estimates. The calculation assumes we have a known population proportion and can determine how much our sample proportions might vary from it due to random sampling.

Practical Applications

To apply this calculator, first identify your population proportion (p) and sample size (n). For example, if 30% of customers prefer a particular product (p = 0.30) and you survey 100 customers (n = 100), the calculator determines the mean (0.30) and standard error (√(0.30 × 0.70 / 100) = 0.0458). You can then use this standard error to construct confidence intervals, determining that approximately 95% of samples will have proportions within two standard errors of the mean. This is essential for quality control, market research, and determining whether observed sample proportions are statistically different from expected values.

Day-to-Day Use

Understanding sampling distributions helps you make better decisions in everyday situations involving surveys and estimates. When a news poll reports that 52% of voters support a candidate with a margin of error, they're using these same principles to tell you the true support likely falls between 49% and 55%. Similarly, when medical studies report treatment effectiveness, the standard error tells doctors how confident they can be in the results. Even when you see a product review stating '90% of users are satisfied,' knowing that this percentage comes from a sample (not every user) and understanding the potential variation helps you gauge how much you should trust that claim for your own purchasing decisions.

Worked example

p 0.4, n 100 → mean 0.4, SE ≈ 0.049.

FAQ

When is it normal?

When both np ≥ 10 and n(1−p) ≥ 10.