Continuity Correction Calculator

Apply a ±0.5 continuity correction to a discrete value.

Corrected boundary 10.5

Formula: Adjust x by ±0.5 to approximate discrete with continuous

Step-by-step with your numbers:
1. Values used:
2. Value = 10
3.
4. Corrected boundary = 10.5
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When approximating a discrete distribution with a normal curve, shift boundaries by 0.5.

How the Math Works

The continuity correction adjusts discrete values by ±0.5 to bridge the gap between discrete distributions (like binomial or Poisson) and their continuous approximations (like normal distribution). When approximating a discrete random variable with a continuous one, this correction accounts for the 'jumps' between integer values. For example, if a discrete variable X takes integer values, P(X ≤ x) in discrete terms becomes P(X ≤ x + 0.5) in the continuous approximation, and P(X > x) becomes P(X > x + 0.5). This adjustment improves accuracy in statistical modeling by aligning discrete and continuous probability boundaries.

Practical Applications

To apply this correction, first identify the discrete value x you want to approximate. Add or subtract 0.5 depending on the inequality: for P(X ≤ x), use x + 0.5; for P(X > x), use x + 0.5 (since the continuous model treats the boundary as a smooth curve). For instance, calculating P(X ≥ 10) for a binomial distribution with n=100 and p=0.1 would use the continuity correction to approximate it as P(X ≥ 9.5) in the normal distribution, yielding a more precise result than using x=10 directly.

Day-to-Day Use

This correction is invaluable in real-world scenarios like quality control, medical trials, or polling, where discrete outcomes (e.g., number of defective products, patient responses, or voter preferences) are analyzed using continuous models for simplicity. For example, a factory manager estimating the probability of at least 50 defective items in a shipment can use the continuity correction to refine their normal approximation, leading to better resource allocation and risk management without complex discrete calculations.

Worked example

P(X ≤ 10) → use 10.5 in the normal approximation.

FAQ

Why correct?

It compensates for replacing discrete bars with a smooth curve.