Continuity Correction Calculator

Apply a ±0.5 continuity correction to a discrete value.

Corrected boundary 10.5

Formula: Adjust x by ±0.5 to approximate discrete with continuous

Step-by-step with your numbers:

1. Values used:

2. Value = 10

4. Corrected boundary = 10.5

Did we solve your problem today?

When approximating a discrete distribution with a normal curve, shift boundaries by 0.5.

The math behind it

P(X ≤ x) uses x + 0.5; P(X ≥ x) uses x − 0.5, and so on, to cover each integer's full width.

P(X ≤ 10) → use 10.5 in the normal approximation.

Why correct?

It compensates for replacing discrete bars with a smooth curve.