Normal Force Calculator

Find the normal force on an object resting on a slope.

Normal force (N) 98.1

Formula: N = m·g·cosθ

Step-by-step with your numbers:
1. Values used:
2. Mass = 10
3. Surface angle = 0 °
4. Gravity = 9.81 m/s²
5.
6. Normal force = 98.1N
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The normal force is the support force a surface pushes back with, perpendicular to it.

How the Math Works

The normal force on an object on a slope is calculated using N = m·g·cosθ, where m is the object's mass, g is gravitational acceleration (9.8 m/s²), and θ is the incline angle. This formula arises because gravity acts vertically, but the slope's surface only supports the component of weight perpendicular to it. The cosine of θ gives this perpendicular component, reducing the normal force as the slope steepens. At 0° (flat ground), cosθ = 1, so N equals the full weight (mg). At 90° (vertical cliff), cosθ = 0, meaning no normal force exists.

Practical Applications

To use this calculator, input the object's mass (in kg) and the slope's angle (in degrees or radians). For example, a 10 kg box on a 30° ramp yields N = 10·9.8·cos(30°) ≈ 84.87 N. Engineers apply this when designing ramps, roofs, or inclined conveyor belts to ensure supports can handle perpendicular forces. It's also used in physics experiments to verify friction calculations or analyze equilibrium on slopes.

Day-to-Day Use

This concept helps in everyday scenarios like safely designing wheelchair ramps to prevent tipping, ensuring car stability on steep roads, or understanding sports equipment design (e.g., skateboard ramps). When hiking or skiing, it explains why objects slide more easily on steeper slopes—less normal force means less friction. Even in daily tasks like moving furniture down a ramp, knowing the normal force helps anticipate stability and required support.

Worked example

10 kg on a 0° surface → 98.1 N.

FAQ

Why does it shrink on a slope?

Part of gravity acts along the slope, so less presses into the surface.