Inductors in Parallel Calculator

Find total inductance of inductors in parallel.

Total inductance (mH) 6.667

Formula: 1/L = 1/L₁ + 1/L₂ + 1/L₃

Step-by-step with your numbers:

1. Values used:

2. Inductor 1 = 10 mH

3. Inductor 2 = 20 mH

4. Inductor 3 = 0 mH

6. Total inductance = 6.667mH

Did we solve your problem today?

Inductors in parallel combine like resistors in parallel — the total is smaller than the smallest.

The math behind it

1/L = 1/L₁ + 1/L₂ + …. Leave unused inductors at 0.

10 mH ∥ 20 mH → 6.67 mH.

Two equal inductors in parallel?

The total is half of one of them.