Elongation Calculator

Find how much a bar stretches under tension.

Elongation 1

Formula: ΔL = F·L ÷ (A·E)

Step-by-step with your numbers:
1. Values used:
2. Force = 10,000 N
3. Original length = 2
4. Cross-section area = 100 mm²
5. Young's modulus = 200 GPa
6.
7. Elongation = 1
Did we solve your problem today?

A material stretches in proportion to load and length, and inversely to area and stiffness.

How the Math Works

The Elongation Calculator uses the formula ΔL = F·L ÷ (A·E) to determine how much a bar stretches under tension. Here, ΔL represents the change in length, F is the applied force, L is the original length of the bar, A is the cross-sectional area, and E is Young's modulus, a material property indicating stiffness. The formula shows that elongation increases with greater force or original length but decreases with a larger cross-sectional area or stiffer material (higher E). This linear relationship allows precise predictions of deformation in elastic materials under load.

Practical Applications

This calculation is essential in engineering and material science for designing structures like bridges, buildings, and mechanical components. Engineers use it to ensure materials can withstand applied forces without excessive deformation. For example, when selecting steel cables for suspension bridges, the calculator ensures the cables stretch within acceptable limits under the bridge's weight and traffic loads. It also aids in quality control during manufacturing, verifying that materials meet safety standards before deployment in critical applications.

Day-to-Day Use

Understanding elongation helps in everyday decisions involving materials. For instance, when choosing a bike frame, knowing how much it stretches under your weight ensures comfort and safety. It explains why thicker or stiffer materials are used in tools and furniture—they resist bending or stretching. Even in DIY projects, like reinforcing a shelf, this knowledge prevents sagging by selecting materials that won't elongate excessively under load, ensuring durability and functionality in daily life.

Worked example

10 kN on a 2 m steel bar (100 mm², 200 GPa) → 1 mm.

FAQ

What if it stretches too far?

Beyond the yield point it deforms permanently.