Partial Fraction Decomposition Calculator

Decompose (px + q) ÷ ((x − r₁)(x − r₂)) into A/(x − r₁) + B/(x − r₂).

A 1.333
B 1.667

Formula: A = (p·r₁ + q)/(r₁ − r₂), B = (p·r₂ + q)/(r₂ − r₁)

Step-by-step with your numbers:
1. Values used:
2. p (numerator x) = 3
3. q (numerator const) = 1
4. Root r₁ = 1
5. Root r₂ = -2
6.
7. A = 1.333
8. B = 1.667
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Partial fractions split a rational expression into simpler pieces — essential for integration.

How the Math Works

The Partial Fraction Decomposition Calculator breaks down complex rational expressions into simpler components. When faced with a fraction like (px + q) divided by ((x - r₁)(x - r₂)), it splits this into A/(x - r₁) + B/(x - r₂). To find A and B, substitute x = r₁ into the equation, which eliminates the B term, leaving A = (p·r₁ + q)/(r₁ - r₂). Similarly, substituting x = r₂ gives B = (p·r₂ + q)/(r₂ - r₁). These formulas exploit the fact that the denominators (r₁ - r₂) and (r₂ - r₁) are negatives of each other, ensuring the decomposition maintains equality.

Practical Applications

This technique is essential in calculus for integrating rational functions, which often appear in physics and engineering problems. For example, integrating (3x + 5)/((x - 1)(x - 2)) becomes straightforward once decomposed into 8/(x - 1) - 3/(x - 2). It also streamlines solving differential equations in control systems and electrical circuits, where Laplace transforms rely on partial fractions to simplify inverse transformations. Engineers use this to analyze system stability and response.

Day-to-Day Use

While not a daily calculation for most people, partial fraction decomposition underpins technologies we use regularly. Signal processing algorithms in smartphones and audio equipment depend on it to filter and analyze data. Financial models for risk assessment and optimization also rely on such mathematical tools. Understanding these concepts helps students and professionals tackle complex problems in STEM fields, indirectly advancing innovations in medicine, communication, and infrastructure that shape modern life.

Worked example

(3x + 1)/((x − 1)(x + 2)) = (4/3)/(x − 1) + (5/3)/(x + 2).

FAQ

What about repeated or complex roots?

Those need extra terms (e.g. A/(x−r) + B/(x−r)²); this tool handles two distinct real roots.